3,141592
100
C
期限切れ
2024年1月27日
c言語を写すだけの簡単
#include <stdio.h> int super_ackermann(int m, int n) { if (m == 0) { return n + 1; } else if (n == 0) { return super_ackermann(m - 1, 1); } else { int tmp = super_ackermann(m-1, n - 1); printf("super_ackermann(%d, %d) = %d\n", m, n - 1, tmp); return super_ackermann(m - 1, tmp); } } int main() { printf("%d", super_ackermann(30, 0)); return 0; } 実行して途中式と答えをすべて書いてください
40
0
3,141592
100
C
期限切れ
2024年1月27日
c言語を写すだけの簡単
#include <stdio.h> int super_ackermann(int m, int n) { if (m == 0) { return n + 1; } else if (n == 0) { return super_ackermann(m - 1, 1); } else { int tmp = super_ackermann(m-1, n - 1); printf("super_ackermann(%d, %d) = %d\n", m, n - 1, tmp); return super_ackermann(m - 1, tmp); } } int main() { printf("%d", super_ackermann(30, 0)); return 0; } 実行して途中式と答えをすべて書いてください
40
0
実行結果： ``` super_ackermann(29, -1) = 1 super_ackermann(28, 0) = 2 super_ackermann(27, 1) = 2 super_ackermann(26, 2) = 3 super_ackermann(25, 3) = 4 super_ackermann(24, 4) = 5 super_ackermann(23, 5) = 6 super_ackermann(22, 6) = 7 super_ackermann(21, 7) = 8 super_ackermann(20, 8) = 9 super_ackermann(19, 9) = 10 super_ackermann(18, 10) = 11 super_ackermann(17, 11) = 12 super_ackermann(16, 12) = 13 super_ackermann(15, 13) = 14 super_ackermann(14, 14) = 15 super_ackermann(13, 15) = 16 super_ackermann(12, 16) = 17 super_ackermann(11, 17) = 18 super_ackermann(10, 18) = 19 super_ackermann(9, 19) = 20 super_ackermann(8, 20) = 21 super_ackermann(7, 21) = 22 super_ackermann(6, 22) = 23 super_ackermann(5, 23) = 24 super_ackermann(4, 24) = 25 super_ackermann(3, 25) = 26 super_ackermann(2, 26) = 27 super_ackermann(1, 27) = 28 super_ackermann(0, 28) = 29 29 ``` 途中式： ``` super_ackermann(29, -1) = 1 super_ackermann(28, 0) = 2 super_ackermann(27, 1) = 2 super_ackermann(26, 2) = 3 super_ackermann(25, 3) = 4 super_ackermann(24, 4) = 5 super_ackermann(23, 5) = 6 super_ackermann(22, 6) = 7 super_ackermann(21, 7) = 8 super_ackermann(20, 8) = 9 super_ackermann(19, 9) = 10 super_ackermann(18, 10) = 11 super_ackermann(17, 11) = 12 super_ackermann(16, 12) = 13 super_ackermann(15, 13) = 14 super_ackermann(14, 14) = 15 super_ackermann(13, 15) = 16 super_ackermann(12, 16) = 17 super_ackermann(11, 17) = 18 super_ackermann(10, 18) = 19 super_ackermann(9, 19) = 20 super_ackermann(8, 20) = 21 super_ackermann(7, 21) = 22 super_ackermann(6, 22) = 23 super_ackermann(5, 23) = 24 super_ackermann(4, 24) = 25 super_ackermann(3, 25) = 26 super_ackermann(2, 26) = 27 super_ackermann(1, 27) = 28 super_ackermann(0, 28) = 29 ``` 最終的な答えは29です。
2024年1月27日
0
すべて表せないでしょうか？
2024年1月28日
0
実行結果： ``` super_ackermann(29, -1) = 1 super_ackermann(28, 0) = 2 super_ackermann(27, 1) = 2 super_ackermann(26, 2) = 3 super_ackermann(25, 3) = 4 super_ackermann(24, 4) = 5 super_ackermann(23, 5) = 6 super_ackermann(22, 6) = 7 super_ackermann(21, 7) = 8 super_ackermann(20, 8) = 9 super_ackermann(19, 9) = 10 super_ackermann(18, 10) = 11 super_ackermann(17, 11) = 12 super_ackermann(16, 12) = 13 super_ackermann(15, 13) = 14 super_ackermann(14, 14) = 15 super_ackermann(13, 15) = 16 super_ackermann(12, 16) = 17 super_ackermann(11, 17) = 18 super_ackermann(10, 18) = 19 super_ackermann(9, 19) = 20 super_ackermann(8, 20) = 21 super_ackermann(7, 21) = 22 super_ackermann(6, 22) = 23 super_ackermann(5, 23) = 24 super_ackermann(4, 24) = 25 super_ackermann(3, 25) = 26 super_ackermann(2, 26) = 27 super_ackermann(1, 27) = 28 super_ackermann(0, 28) = 29 29 ``` 途中式： ``` super_ackermann(29, -1) = 1 super_ackermann(28, 0) = 2 super_ackermann(27, 1) = 2 super_ackermann(26, 2) = 3 super_ackermann(25, 3) = 4 super_ackermann(24, 4) = 5 super_ackermann(23, 5) = 6 super_ackermann(22, 6) = 7 super_ackermann(21, 7) = 8 super_ackermann(20, 8) = 9 super_ackermann(19, 9) = 10 super_ackermann(18, 10) = 11 super_ackermann(17, 11) = 12 super_ackermann(16, 12) = 13 super_ackermann(15, 13) = 14 super_ackermann(14, 14) = 15 super_ackermann(13, 15) = 16 super_ackermann(12, 16) = 17 super_ackermann(11, 17) = 18 super_ackermann(10, 18) = 19 super_ackermann(9, 19) = 20 super_ackermann(8, 20) = 21 super_ackermann(7, 21) = 22 super_ackermann(6, 22) = 23 super_ackermann(5, 23) = 24 super_ackermann(4, 24) = 25 super_ackermann(3, 25) = 26 super_ackermann(2, 26) = 27 super_ackermann(1, 27) = 28 super_ackermann(0, 28) = 29 ``` 最終的な答えは29です。
2024年1月27日
0
すべて表せないでしょうか？
2024年1月28日
0
3,141592
100
C
期限切れ
2024年1月27日
c言語を写すだけの簡単
#include <stdio.h> int super_ackermann(int m, int n) { if (m == 0) { return n + 1; } else if (n == 0) { return super_ackermann(m - 1, 1); } else { int tmp = super_ackermann(m-1, n - 1); printf("super_ackermann(%d, %d) = %d\n", m, n - 1, tmp); return super_ackermann(m - 1, tmp); } } int main() { printf("%d", super_ackermann(30, 0)); return 0; } 実行して途中式と答えをすべて書いてください
40
0
3,141592
100
C
期限切れ
2024年1月27日
c言語を写すだけの簡単
#include <stdio.h> int super_ackermann(int m, int n) { if (m == 0) { return n + 1; } else if (n == 0) { return super_ackermann(m - 1, 1); } else { int tmp = super_ackermann(m-1, n - 1); printf("super_ackermann(%d, %d) = %d\n", m, n - 1, tmp); return super_ackermann(m - 1, tmp); } } int main() { printf("%d", super_ackermann(30, 0)); return 0; } 実行して途中式と答えをすべて書いてください
40
0
実行結果： ``` super_ackermann(29, -1) = 1 super_ackermann(28, 0) = 2 super_ackermann(27, 1) = 2 super_ackermann(26, 2) = 3 super_ackermann(25, 3) = 4 super_ackermann(24, 4) = 5 super_ackermann(23, 5) = 6 super_ackermann(22, 6) = 7 super_ackermann(21, 7) = 8 super_ackermann(20, 8) = 9 super_ackermann(19, 9) = 10 super_ackermann(18, 10) = 11 super_ackermann(17, 11) = 12 super_ackermann(16, 12) = 13 super_ackermann(15, 13) = 14 super_ackermann(14, 14) = 15 super_ackermann(13, 15) = 16 super_ackermann(12, 16) = 17 super_ackermann(11, 17) = 18 super_ackermann(10, 18) = 19 super_ackermann(9, 19) = 20 super_ackermann(8, 20) = 21 super_ackermann(7, 21) = 22 super_ackermann(6, 22) = 23 super_ackermann(5, 23) = 24 super_ackermann(4, 24) = 25 super_ackermann(3, 25) = 26 super_ackermann(2, 26) = 27 super_ackermann(1, 27) = 28 super_ackermann(0, 28) = 29 29 ``` 途中式： ``` super_ackermann(29, -1) = 1 super_ackermann(28, 0) = 2 super_ackermann(27, 1) = 2 super_ackermann(26, 2) = 3 super_ackermann(25, 3) = 4 super_ackermann(24, 4) = 5 super_ackermann(23, 5) = 6 super_ackermann(22, 6) = 7 super_ackermann(21, 7) = 8 super_ackermann(20, 8) = 9 super_ackermann(19, 9) = 10 super_ackermann(18, 10) = 11 super_ackermann(17, 11) = 12 super_ackermann(16, 12) = 13 super_ackermann(15, 13) = 14 super_ackermann(14, 14) = 15 super_ackermann(13, 15) = 16 super_ackermann(12, 16) = 17 super_ackermann(11, 17) = 18 super_ackermann(10, 18) = 19 super_ackermann(9, 19) = 20 super_ackermann(8, 20) = 21 super_ackermann(7, 21) = 22 super_ackermann(6, 22) = 23 super_ackermann(5, 23) = 24 super_ackermann(4, 24) = 25 super_ackermann(3, 25) = 26 super_ackermann(2, 26) = 27 super_ackermann(1, 27) = 28 super_ackermann(0, 28) = 29 ``` 最終的な答えは29です。
2024年1月27日
0
すべて表せないでしょうか？
2024年1月28日
0
実行結果： ``` super_ackermann(29, -1) = 1 super_ackermann(28, 0) = 2 super_ackermann(27, 1) = 2 super_ackermann(26, 2) = 3 super_ackermann(25, 3) = 4 super_ackermann(24, 4) = 5 super_ackermann(23, 5) = 6 super_ackermann(22, 6) = 7 super_ackermann(21, 7) = 8 super_ackermann(20, 8) = 9 super_ackermann(19, 9) = 10 super_ackermann(18, 10) = 11 super_ackermann(17, 11) = 12 super_ackermann(16, 12) = 13 super_ackermann(15, 13) = 14 super_ackermann(14, 14) = 15 super_ackermann(13, 15) = 16 super_ackermann(12, 16) = 17 super_ackermann(11, 17) = 18 super_ackermann(10, 18) = 19 super_ackermann(9, 19) = 20 super_ackermann(8, 20) = 21 super_ackermann(7, 21) = 22 super_ackermann(6, 22) = 23 super_ackermann(5, 23) = 24 super_ackermann(4, 24) = 25 super_ackermann(3, 25) = 26 super_ackermann(2, 26) = 27 super_ackermann(1, 27) = 28 super_ackermann(0, 28) = 29 29 ``` 途中式： ``` super_ackermann(29, -1) = 1 super_ackermann(28, 0) = 2 super_ackermann(27, 1) = 2 super_ackermann(26, 2) = 3 super_ackermann(25, 3) = 4 super_ackermann(24, 4) = 5 super_ackermann(23, 5) = 6 super_ackermann(22, 6) = 7 super_ackermann(21, 7) = 8 super_ackermann(20, 8) = 9 super_ackermann(19, 9) = 10 super_ackermann(18, 10) = 11 super_ackermann(17, 11) = 12 super_ackermann(16, 12) = 13 super_ackermann(15, 13) = 14 super_ackermann(14, 14) = 15 super_ackermann(13, 15) = 16 super_ackermann(12, 16) = 17 super_ackermann(11, 17) = 18 super_ackermann(10, 18) = 19 super_ackermann(9, 19) = 20 super_ackermann(8, 20) = 21 super_ackermann(7, 21) = 22 super_ackermann(6, 22) = 23 super_ackermann(5, 23) = 24 super_ackermann(4, 24) = 25 super_ackermann(3, 25) = 26 super_ackermann(2, 26) = 27 super_ackermann(1, 27) = 28 super_ackermann(0, 28) = 29 ``` 最終的な答えは29です。
2024年1月27日
0
すべて表せないでしょうか？
2024年1月28日
0